A 12 ohm resistor is connected in series with a parallel combination of 10 resistors each of 200 ohm. what is the net resistance of the circuit?

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00:00question is a 12 ohm resistor is connected in series with a parallel combination of 10

00:16resistors each of 200 ohm what is the net resistance of the circuit first of all we

00:27will form a data is R1 is obtained is 12 ohm and the value of 10 resistors is 200 ohm means R2 to R11

00:50the value is 200 ohm and the number of resistors is 10 first of all we will find R' and then equivalent

01:10resistance so for solution is when 10 resistors of same value are in parallel combination so their

01:25equivalent resistance R' will be equal to R upon N so here's R2 to R11 is equal to

01:39200 ohm which is equal to R so the value of R is 200 divided by number of resistors which are 10

01:53so R' will be obtained is 200 divided by 10 it will be 20 ohm is R1 means 12 ohm resistor is connected in

02:15series with the parallel combination of 10 resistors so now net resistance means equivalent resistance

02:26will be equal to R1 plus R' because R1 is connected in series with R' so equivalent resistance will be

02:41equal to 12 plus R' which is 20 ohm so equivalent resistance will be obtained as 32 ohm this is our final answer