Resistors of 20Ω,40Ω and 50Ω are connected in parallel across a 50V power source.Find the equivalent resistance of the set and the current in each resistor ? Physics class 12 problem solution Inter class physics problem solution Current electricity problems solution Electrodynamics problem solution
00:00question is resistors of 20 ohm 40 ohm 50 ohm are connected in parallel across a 50 volt power
00:17source find the equivalent resistance of the set and the current in each resistor
00:25is there are three resistors which are R1 R2 and R3 are connected in parallel combination
00:48across 50 volt potential difference r1 is
01:0820 ohm R2 is 40 ohm and R3 is 50 ohm first of all we will make a data
01:28R1 is obtained is 20 ohm R2 is obtained is 40 ohm R3 is obtained is 50 ohm and electric potential is
01:52obtained is 50 volts so we have to find their equivalent resistance and current in each
02:06resistors so I1 I2 and I3 is equal to watt here resistors are in parallel combination so their
02:23electric potential will be same but electric current will be different in each the resistors
02:29so we have to find their electric currents and their equivalent resistance first of all we
02:40will find their equivalent resistance is in solution their equivalent resistance will be equal to 1 upon
02:55R1 plus 1 upon R1 plus 1 upon R2 plus 1 upon R3 so equivalent resistance will be obtained is 1 upon R1 R1 is 20 plus 1 upon R2 R2 is 40 plus 1 upon R3 R3 is 50
03:19so we will take the LCM of R3 so we will take the LCM of 20 40 and 50 so 1 upon R3 means equivalent resistance will be obtained is is the LCM of 20 40 and 50 is obtained as 200 so the table of 20 and 200 is 10 times so 1 into 10 it will be 10 plus the table of 40
03:49on 200 on 200 is 50 on 200 is 50 on 200 is 4 times so 4 into 100 is 4 times so 4 into 1 it will be 4 so equivalent resistance will be obtained as 10 plus 5 plus 4 it will be 19 upon 200
04:11so 1 upon r is equal to 19 upon 200 so 1 upon r is equal to 19 upon 200 so r will be equal to 200 upon 19 so r e will be obtained as 200 divided by 19 it will be obtained as 10.5
04:38as 10.5 ohm so we have found equivalent resistance is 10.5 ohm so we have found equivalent resistance is 10.5 ohm now we will find the current through each resistor
04:55first we will find the current through r1 which is i1 is i1 is i1 is equal to v upon r1 so v is obtained as 50 and r1 is obtained as 20
05:22so 50 divided by 20 it will be 2.5 ampere so i1 is obtained as 2.5 ampere now i2 which is equal to v upon r2 is
05:47their resistors their resistors their resistors their resistors their resistors are in parallel so their electric potential will be same means v
05:54is electric potential is 50 divided by r2 which is 40 so i2 will be obtained as 50 divided by 40 it will be obtained as 1.25 ampere
06:14so i2 is obtained as 1.25 ampere so i2 is obtained as 1.25 ampere finally we will find i3 which is equal to v upon r3
06:31so v3 asgew ovkl, which is equal to is equal to vue .bps and r3 tablespoon plus v1 is 500 . jornal
06:37so i3 will ay3 which is obtained as 50 divided by 50 if we have written efCC by 154
06:47so i3 will be obtained as 50 divided by 50 it will be 1 ampere so i3 is obtained is 1 ampere so these are our required answers
