00:00question is currents of 3 ampere and 1.5 ampere flow through two wires one that has a potential
00:15difference of 60 volts across its ends and an other that has a potential difference of 120
00:24volts across its ends compare the rate at which energy pass through each wire so first of all we
00:36will form a data is first current I1 is obtained as 3 ampere and second current I2 is obtained as
00:541.5 ampere and first voltage V1 is obtained as 60 volt and second voltage V2 is obtained as 120 volt
01:11so we have to find the ratio of powers means p1 upon p2 is equal to watt in solution
01:27first we find p1 which is equal to I1 into V1 so p1 is equal to I1 is 3 into V1 which is 60 volt
01:51so p1 will be obtained as 3 into 60 it will be 180 watt so p1 is obtained as 180 watt
02:05now p2 which is equal to I2 into V2 so p2 will be equal to as I2 is 1.5 ampere
02:28V2 into V2 is 120 volt so p2 will be obtained as 1.5 into 120 so it will be 180 watt as p2 is also obtained as
02:58180 watt finally we will find the ratio p1 upon p2 which is equal to as the value of p1 is 180 and the value of p2 is also 180 so the table of 180 on 180 is 1 times so it will be 1 upon 1
03:26so p1 ratio p2 is obtained as 1 ratio 1 so this is our final answer
