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  • 7/5/2025
Physics class 12 mcqs solution
Inter class physics mcqs solution
Mdcat Physics mcqs solution
Electronics mcqs solution
Transcript
00:00The question says, if collector current is equal to 4 mA and current gain is 45, then
00:18the emitter current is a 4.1 mA, b 4.02 mA, c 4.4 mA, d 4.04 mA. We have to find the emitter
00:37current. So, is emitter current is equal to the sum of collector current and base current.
00:53So, here collector current is obtained, but base current is not obtained. So, first of
01:02all, we will find base current is current gain means beta is equal to the ratio of collector
01:16current and base current. So, we have to find base current. So, this equation will become
01:26is base current will be equal to collector current divided by current gain means beta. Because
01:37when we will take base current to the other side of equal, then it will multiply with beta.
01:44And when we will take beta on the other side of equal, then it will divide. So, now by putting
01:52the given value in the given value is collector current is obtained as 4 mA divided by current
02:05gain means beta which is 45. So, base current will be obtained as 4 divided by 45, then it will
02:19be 0.088 mA. Now, we will find emitter current which is equal to the sum of collector current
02:37and base current. So, emitter current will be equal to is collector current is obtained as
02:474.088 mA. So, emitter current will be equal to 4.088 mA because 4 plus 0.088 mA then it will
03:11be 4.088 mA. When we will round off this value then we will get 4.1 mA. So, the correct option
03:32will be A, 4.1 mA. So, the solution will be A, 4.1 mA. So, the solution will be A, 4.1 mA.
03:39So, the solution will be B and nó is about 802 mA. So, when you have more, you've already

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