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The Mass of PbF2 From Solubility Product Constant
Rebiaz Studio
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9/20/2024
The amount of Lead (II) Fluoride is dissolved in 250 ml of water until the solution is exactly saturated. What is the mass of PbF2, if the solubility product constant of PbF2 is 2.7x10⁻⁸.
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00:00
The amount of lead-2-fluoride is dissolved in 250 mL of water until the solution is exactly saturated.
00:08
The question is, what is the mass of PbF2, if the solubility product constant of PbF2 is 2.7 x 10-8?
00:19
OK, the first step is identification.
00:22
The volume of water, V is equal to 0.25 liters.
00:27
Ksp of PbF2 is equal to 2.7 x 10-8.
00:34
The relative molecular mass of lead-2-fluoride, 207.2 plus 2 x 19.
00:43
The result is 245.2 g per mole.
00:49
The next step is to analyze the ion equilibrium.
00:56
In water, a molecule of lead-2-fluoride ionizes into a Pb2 plus ion and 2 F minus ions.
01:04
The Ksp value in saturated and supersaturated solutions is exactly the same.
01:10
The following illustration is a supersaturated condition because there is already a precipitate in the solution.
01:17
Assume that the number of Pb2 plus ions is S mole.
01:22
So the number of F minus ions is 2 S mole.
01:27
And the volume of the solution is 1 liter.
01:33
So the molarity of Pb2 plus ions is S molar.
01:37
And the molarity of F minus ions is 2 S molar.
01:42
The next step is to write the chemical equilibrium equation.
01:47
A molecule of PbF2 will ionize into a lead ion, 2 fluoride ions.
01:54
Now, we can calculate the value of S from the Ksp equation.
01:59
Ksp is equal to the concentration of Pb2 plus ions, multiplied by the concentration of F minus ions to the power of 2.
02:09
Plugging in the values of ion concentration and Ksp.
02:15
For S to the power of 3 is equal to 2.7 times 10 to the power of negative 8.
02:23
We can write this equation as S to the power of 3.
02:29
Using a calculator, S is about 1.89 times 10 to the power of negative 3.
02:37
This value of S is also the value of moles of PbF2 dissolved in 1 liter of water in a perfectly saturated solution.
02:49
So, the molarity of PbF2 is 1.89 times 10 to the power of negative 3 molar.
02:58
The fifth step is to calculate the mass of PbF2.
03:02
Using the concept of molarity, big M equals N over V.
03:08
Putting both values in.
03:11
N equals 4.75 times 10 to the power of negative 4 moles.
03:17
This is the mole value of PbF2 in a 250 milliliter solution.
03:23
The mass of PbF2 dissolved is N times the relative molecular mass.
03:28
Putting both values in.
03:31
The result is equal to 0.115857 grams or 115.9 milligrams.
03:41
This is the mass of PbF2 dissolved in 250 milliliters of water so that the solution is exactly saturated.
03:51
Yup, hopefully useful.
03:53
And, don't forget to follow this channel.
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