The mass of the planet Jupiter is 1.9×10^27 kg and that of the sun is 2×10^30 kg.If the average distance between them is 7.8×10^11m.Find the gravitational force of the sun on Jupiter. Physics class 11th problems solution First year physics problems solution Physics class 11th numericals solution First year physics numericals solution Gravitation problems
00:00Question is, the mass of the planet Jupiter is 1.9 into 10 raised power 27 kilogram and
00:12that of the sun is 2 into 10 raised power 30 kilogram. If the average distance between
00:21them is 7.8 into 10 raised power 11 meters, find the gravitational force of the sun on
00:29the Jupiter. Is, Is question में कहराएं कि Jupiter का जो मास है वो हमें
00:40आप्टेंड है और sun का मास भी हमें आप्टेंड है और Jupiter और sun के
00:44दर्मियान जो distance है वो भी हमें आप्टेंड है तो हमें sun का जो
00:49force है Jupiter पे gravitational वो gravitational force हम find करेंगे.
00:56So, first of all we will make a data is the mass of Jupiter is obtained is 1.9 into 10
01:14raised power 27 kilogram, the mass of sun is obtained is 2 into 10 raised power 30 kilogram
01:27and the distance between sun and Jupiter is given is 7.8 into 10 raised power 11 meter.
01:40So, we have to find force of sun on Jupiter means gravitational force of sun on Jupiter.
01:53So, for solution, we will use the formula for Newton's law of universal gravitation is the
02:07force of sun on Jupiter is calculated by using formula F is equal to G into mass of Jupiter
02:17and the mass of sun divided by r squares is the gravitational force will be equal to is the value of G
02:34G, capital G is constant which is the value of G is 6.67 into 10 raised power minus 11 newton
02:46into meter square per kilogram square. So, by putting the given values 6.67 into 10 raised power minus 11
02:59into the mass of Jupiter is 1.9 into 10 raised power 27 multiplied with mass of sun which is
03:112 into 10 raised power 30 kilogram divided by r square. Here r is the distance between sun and Jupiter which is given as
03:237.8 into 10 raised power minus 7.8 into 10 raised power 11 meter whole square. As after simplifying the above values
03:35we will get as means 6.67 into 1.9 into 2. It will be 25.346 into as here
03:52in multiplication when bases are same then we will add the powers. So, it will be minus 11 plus 27 plus 30 divided by the square of 7.8 is 60.84 into 10 raised power into 10 raised power 11 power 2. So, it will be
04:2111 into 2. So, it will be 22. So, the gravitational force will be obtained as 25.346 divided by 60.84. It will be obtained as 0.4166 into 10 raised power is
04:47minus 11 plus 27 minus 11 plus 27 plus 30. So, it will be plus 46 divided by plus 22. So, when we will take plus 22 in the numerators. So, it will be minus 22. So, the gravitational force will be obtained as
05:170.4166 into 10 raised power is 0.4166 into 10 raised power 46 minus 22. So, it will be plus 24 Newton or we can also write this as the gravitational force will be
05:240.4166 to 10 raised power is 0.4166 to 10 raised power of 46 minus 22. So, it will be plus 24 Newton or we can also write this as the gravitational force will be
05:42So when we will shift this decimal one digit from left to right then we will subtract 1
05:54from the power.
05:56So this will become as 4.166 into 10 raised power 23 Newton.
06:09So this is our required answer.
06:14Means the gravitational force of Sun on the Jupiter is 4.166 into 10 raised power 23 Newton.
