Compute gravitational acceleration at the surface of the planet Jupiter which has a diameter as 11 times as compared with that of the earth and a mass equal to 318 times that of earth Physics class 11th problems Physics class 11th numericals First year physics problems Gravitation problems solution
00:00Question is, compute the gravitational acceleration at the surface of the planet Jupiter which
00:15has a diameter 11 times as compared with that of the Earth and mass equal to 318 times that
00:26of the Earth. So, first of all we will make a data is mass of Jupiter is equal to 318 times
00:49mass of Earth and diameter of Jupiter is equal to 11 times diameter of Earth. So, radius
01:04of Jupiter is also equal to 11 times radius of Earth. So, we have to find acceleration
01:16due to gravity on Jupiter. So, for solution, on the surface of Earth, the formula for small
01:34G is, G is equal to GME upon RE square. So, this is equation number 1. G on Jupiter is calculated
01:57by using formula, G on Jupiter is equal to G into mass of Jupiter divided by radius of Jupiter
02:11is, mass of Jupiter is equal to 318 times mass of Earth divided by radius, the square of
02:39the radius of the radius of the radius of Jupiter which is equal to the 11 RE whole square. So, G
02:52on Jupiter will be equal to G into 318 ME divided by the square of 11 is 121, the square of RE
03:08the square of the radius of the radius of the radius of the radius of the radius of the radius. So,
03:14the value of G on Jupiter will be equal to 318 divided by 121 into GME upon RE square.
03:27So, G on Jupiter will be equal to G. So, G on Jupiter will be equal to G. So, G on Jupiter will be equal
03:34to, after simplifying this, we will get the answer is 2.63 into G into ME upon RE square is equal to G. So,
03:54this is our first required condition or we can also further simplify it as R. G on Jupiter is equal to 2.63 into G as the value of G on the surface of Earth is 9.8 meter per second square. So, G on Jupiter will be obtained as
04:01when we will multiply these values we will get the answer is 25.3 into G. So, G on Jupiter is equal to 2.63 into G as the value of G on the surface of Earth is 9.8 meter per second square. So, G on Jupiter is equal to 2.63 into G as the value of G on the surface of Earth is 9.8
04:18meter per second square. So, G on Jupiter will be obtained as when we will multiply these values we will get the answer is 25.75 meter per second square.
04:37So, this is our final required condition. So, the value of G on the surface of Jupiter is 25.75 or we can also write it as 26 meter per second square. So, this is our required answer.