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Laws of Motion -07- The Magnitude of Hinge Force
Rebiaz Studio
Follow
9/24/2024
The rod shown in figure has a mass of 3 kg and length 3 m. In equilibrium, find the hinge force (or its two components) acting on the rod and tension in the string. Take g = 10 m/s², sin 53° = 4/5, cos 53° = 3/5.
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Learning
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00:00
Hi friends, no matter whether it is Tuesday or Sunday, if you have a high goal in life,
00:06
you must work hard every day to achieve it.
00:11
We often see hinges on windows or doors.
00:14
This time we will learn to calculate the magnitude of the hinge force.
00:20
One end of the stick is connected to the hinge, while the other end is connected to a rope
00:24
attached to the wall.
00:26
What is the magnitude of the hinge force?
00:31
Let's discuss it.
00:34
As usual, we have to draw a free body diagram of this system.
00:40
The centre of mass of the stick is in the middle of the stick.
00:44
So the force of gravity will act from the centre of mass of the stick.
00:50
The rope is tense because of the tension force of the rope.
00:55
For the force at the hinge, we do not know the magnitude and direction of this force.
01:00
However, we know that each force can be resolved into vector components, what if the hinge
01:05
force has a horizontal component H and a vertical component V?
01:13
Of all these forces, the direction of the tension force of the rope is not the same.
01:18
We also have to resolve this force into component vectors.
01:24
This stick is in equilibrium.
01:27
This means that the resultant force acting on the stick is zero.
01:32
For the resultant force in the horizontal direction, H minus T cosine 53 is equal to zero.
01:41
For the resultant force in the vertical direction, V plus T sine 53 minus W is equal to zero.
01:50
We already know the values of sine, cosine and W from the problem sheet.
01:58
We have two equations with three unknown quantities.
02:01
We need one more equation.
02:06
We know that the stick does not rotate, so the torque acting on the stick is also equal
02:10
to zero.
02:14
Because the axis is a hinge, H and V do not have a moment arm.
02:18
The moment arm is only owned by W and the vertical component of the rope tension.
02:26
As before, just enter the values that have been listed on the problem sheet.
02:32
This is an easy calculation, T is about 18.75 Newtons.
02:41
Knowing the value of T, we can substitute this value into the previous equation.
02:48
H is equal to 11.25 Newtons.
02:54
And V is equal to 15 Newtons.
02:59
H and V are components of the hinge force.
03:04
The magnitude of the hinge force itself is the square root of H squared plus V squared.
03:12
We can calculate this value using a calculator.
03:16
F hinge is about 18.75 Newton.
03:22
It turns out that the magnitude of the hinge force is exactly the same as the tension force
03:26
of the rope.
03:29
Happy learning everyone!
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