Circular Motion | Circular Motion Class 11 | Banking Of Roads physics Class 11 | Banking Of Roads | Banking Of Roads Physics | Banking Of Roads class 11 JEE | Banking Of Roads class 11 NEET - video Dailymotion

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Circular Motion | Circular Motion Class 11 | Banking Of Roads physics Class 11 | Banking Of Roads | Banking Of Roads Physics | Banking Of Roads class 11 JEE | Banking Of Roads class 11 NEET   Explore the fascinating world of circular motion and the concept of banking of roads in physics class 11. Learn about the principles behind circular motion and the importance of banking roads for safe driving. This video tutorial will cover the basics and applications of these concepts to enhance your understanding of physics.   #srbphysicskota #srbphysics #circularmotion #circularmotionjee #circularmotiononeshot #physics #banking #bankingofroads #aksir #aksirphysics #centrepetalacceleration   Circular Motion, Circular Motion Class 11, Banking Of Roads physics Class 11, Banking Of Roads, Banking Of Roads physics Class 11 derivation, banking of tracks physics class 11, banking one shot class 12, Banking Of Roads physics Class 11 numericals, Banking Of Roads physics Class 11 physics wallah, Banking Of Roads physics Class 11 animation, Banking Of Roads physics Class 11 questions, Banking Of Roads physics Class 11 exam winner, Banking Of Roads jee, Banking Of Roads jee mains, Banking Of Roads physics class 11 jee, Banking Of Roads physics class 11 neet, banking of tracks physics class 11 numericals, banking of tracks physics Class 11th Physics, Circular Motion Class 11 JEE, circular motion class 11 NEET, circular motion class 11 jee one shot, uniform circular motion, uniform circular motion class 11 one shot,  uniform circular motion class 11 physics wallah, uniform circular motion class 11th, neet circular motion, neet circular motion pyq, jee main circular motion, jee circular motion, jee circular motion pyq, jee circular motion questions, angular displacement,  angular displacement physics class 11,  angular displacement and angular velocity,  angular displacement definition,  angular velocity,  angular velocity and angular acceleration,  angular velocity physics class 11,  angular velocity formula,  angular acceleration,  angular acceleration physics class 11,  equation of motion,  equation of motion class 11,  equation of motion by calculus method class 11 physics,  Circular Motion Class 11 live, Circular Motion live, Class 11th Physics live, Circular Motion Class 11 JEE live, circular motion class 11 NEET live, circular motion physics wallah, circular motion class 11 one shot live, uniform circular motion class 11 live, uniform circular motion live, uniform circular motion class 11 one shot live, uniform circular motion physics live, Circular Motion | Circular Motion Class 11 | Banking Of Roads physics Class 11 | Banking Of Roads, Banking Of Roads Physics, Banking Of Roads class 11 JEE, Banking Of Roads class 11 NEET,

Transcript

00:00see today we will start banking off-road

00:04what will we start? Banking off-road

00:07we will start, see in banking off-road

00:12we will first tell about banking off-road on smooth surface

00:17yes banking off-road we are telling that, banking off-road means

00:22when any body, car, bike or any vehicle

00:27turns on a turn, so the turn

00:31we call it banking, what do we call it?

00:34banking, the turn there

00:38the road there is inclined, how is it?

00:41inclined, it is on theta angle

00:44if you have any doubt, you can ask

00:46you?

00:48you can ask

00:51no

00:52see here

00:54when any vehicle, see here we have taken a car

00:57it will turn on a turn, when it will turn on a turn

01:00it will become a circular path

01:03when it will turn on a circular path

01:05so the road here is a little inclined

01:08it is on theta angle

01:12so what is the velocity?

01:14the relation between velocity and angle

01:16we will tell that in this

01:18so see here the diagram we have taken

01:21in this, there is a car

01:23when the car will turn on a turn

01:25so its velocity will be V

01:27and a normal reaction

01:31here I have taken its center C

01:33and the radius of this circular path

01:37will be R

01:39so here we will do its component

01:41what all forces will be applied on this?

01:45we are drawing FBD

01:47FBD of M

01:49draw it

01:53this will be MG

01:55in this direction

01:57we will take normal reaction

01:59this will be theta angle

02:03and

02:07we will do two components of this

02:09here this will be centripetal acceleration

02:11AC

02:13this is mass

02:15see here

02:17when we will do two components

02:19of normal reaction

02:21this will come in this direction

02:23n cos theta

02:25and in this direction

02:27n sin theta

02:29no problem

02:31n cos theta

02:33will be equal to MG

02:35because in this direction

02:37there is no acceleration in vertical

02:39so the equation

02:41n cos theta

02:43will be equal to MG

02:47and

02:49n sin theta

02:51is giving centripetal acceleration

02:53n sin theta

02:55is equal to

02:57M into

02:59AC

03:01we will write first equation

03:03and second equation

03:05if you have any problem

03:07you can ask

03:09see here n cos theta

03:11here normal reaction

03:13we will take perpendicular to plane

03:15this will be normal reaction

03:17in this direction n cos theta

03:19will be one component

03:21and here

03:23n sin theta

03:25n sin theta will provide centripetal

03:27acceleration

03:29so n sin theta

03:31will be equal to M into AC

03:33and n cos theta will be equal to MG

03:35no doubt

03:37now divide these two equations

03:39first and second

03:41divide

03:43in first equation

03:45divide in second equation

03:47n sin theta

03:49divided by

03:51n cos theta

03:53is equal to M into AC

03:55and this will be equal to MG

03:57see we will not teach much today

03:59we will teach little

04:01we will complete

04:03banking off road

04:05see here

04:07M is cancelled from M

04:09normal reaction is cancelled

04:11here sin theta upon cos theta

04:13what is it?

04:15tan theta

04:17is it or not?

04:19any problem?

04:21no

04:23AC is not value of

04:25centripetal acceleration

04:27P square by

04:29very good

04:31you tell

04:37P square by

04:39R

04:41this formula will be

04:43here this relation

04:45you have to remember

04:47in banking off road

04:49this tan theta value

04:51is

04:59tan theta

05:01is equal to

05:03V square by R

05:05you have to remember this formula

05:07in banking off road

05:09we will apply this

05:11any doubt?

05:13R is radius of circular path

05:15V is speed by which

05:17body is moving on circular turn

05:19that is V velocity

05:21and G is acceleration due to gravity

05:23any doubt?

05:25you don't have?

05:27no one?

05:29very good

05:31see we have taken

05:33this question

05:35this is the question

05:41you are not smart

05:43study

05:47you will not study

05:49very good

05:51you don't know smartness

05:53you did right or wrong

05:55radius of the curve

05:57road on

05:59national highway

06:01is R

06:03radius is

06:05R

06:07radius of third road

06:09is R

06:11width of road is

06:13B

06:15width of road is

06:17B

06:19outer edge

06:21of the road

06:23is raised by

06:25H with respect to

06:27inner edge

06:33so

06:35in respect to inner edge

06:37outer edge height

06:39will be more

06:41how much?

06:43H

06:45with respect to inner edge

06:47so that a car

06:49with velocity V can pass

06:51safely over it

06:53so if there is a car

06:55cross it safely with speed

06:57means

06:59there should not be accident

07:01so

07:03we have to find

07:05value of H

07:07so first of all

07:09we make a diagram

07:11this is road

07:13this is theta angle

07:19width of road is

07:21B

07:23height is

07:25H

07:27ok

07:29now

07:31in this car will pass

07:33its velocity is V

07:35from here we will make a car

07:37pass

07:41this car is passing

07:43its velocity is V

07:45so the radius of

07:47circular path of V

07:49will be

07:51radius R

07:53any problem?

07:55so here the formula is

07:57tan theta

07:59is equal to

08:01V square by

08:03RG

08:05this formula was told

08:07few minutes ago

08:09tan theta is

08:11perpendicular upon

08:13base

08:15tan theta is

08:17hypotenuse

08:19from here

08:21when we write tan theta

08:23how much we will write?

08:25tan theta is equal to H

08:27and base will be B

08:33from here question asked

08:35value of height

08:37so height H will be

08:39P square

08:43P

08:47upon

08:49RG

08:51you know

08:53you said

08:57so this height will be

08:59P square

09:01by RG

09:03I hope you will not have any problem

09:09move ahead

09:13ok this question

09:15you try to solve

09:23a guy holds a pendulum

09:25in his hand

09:27while standing at the edge

09:29of a circular

09:31platform of

09:33radius R

09:35rotating with an angular

09:37speed omega

09:41let us leave this

09:43for later

09:45let us

09:47study banking

09:49ok

09:51this was told

09:53on smooth surface

09:55now

09:57we are going to take

09:59rough surface

10:01what kind of surface?

10:03rough surface

10:05where

10:07there is friction

10:09here we will take

10:11rough surface

10:13motion of object

10:15on rough inclined circular

10:17path

10:19when a body moves

10:21on inclined circular path

10:23in that condition

10:25its motion will be

10:27velocity

10:29from minimum velocity

10:31to maximum velocity

10:33in range of velocity

10:35we can do anything

10:37clear

10:39rough

10:41circular path

10:43from minimum velocity

10:45to maximum velocity

10:47on any velocity

10:49you can pass any excuse

10:51no doubt

10:53no

10:55now you have to see

10:57what is the value

10:59to cross safely

11:01what will be Vmax

11:03maximum velocity

11:05will be when

11:07centripetal force

11:09friction centripetal

11:11force

11:13will be supported

11:15hello

11:17support

11:19here

11:21body is moving

11:23here

11:25friction is taken

11:27down the plane

11:29in two directions

11:31one is down the plane

11:33second

11:35up the plane

11:37away from the center

11:39and down the plane

11:41will be

11:43towards

11:45center

11:47that is why

11:49friction is taken

11:51down the plane

11:53because we need

11:55maximum velocity

11:57maximum

11:59yes

12:01towards center

12:03centripetal force is supported

12:05by friction

12:07yes

12:09normal reaction

12:11downward

12:13mg

12:15diagram

12:17fbd

12:19yes

12:21it is difficult

12:23difficult

12:25means

12:27it is difficult

12:29you have to pay attention

12:31this is

12:33theta

12:35this is normal

12:37this angle is also theta

12:39and here

12:41in this direction

12:43this normal reaction

12:45will have one component

12:47in this direction n

12:49cos theta and in this direction

12:51n sin theta

12:53I hope there will be no problem

12:55friction fs limiting

12:57we have put in this direction

12:59where we have put fs

13:01limiting

13:03this angle is theta

13:05so what will be this angle

13:07so according to this

13:09what will be this angle

13:11theta

13:13means fs

13:15friction's one component

13:17will come in this direction

13:19fs limiting

13:21cos theta will come in this direction

13:23and fs limiting

13:25sin theta

13:27will come in this direction

13:29and this

13:31will be in this direction

13:33centripetal axis

13:35this is a beautiful diagram

13:37n cos theta

13:39this is normal reaction's component

13:41will be in this direction

13:43n sin theta will come in this direction

13:45friction fs limiting

13:47down the plane

13:49one component of this

13:51fs limiting cos theta will come in this direction

13:53left

13:55second one will be downward

13:57fs limiting

13:59sin theta

14:01now here we will equal their components

14:03so here

14:05n cos theta

14:07will be

14:09mg plus fs limiting

14:11sin theta

14:13no problem

14:15n cos theta

14:17is equal to

14:19n cos theta

14:21is equal to

14:23mg plus fs limiting

14:25sin theta

14:27fs limiting value is

14:29mu s into

14:31n

14:33so this is mg

14:35plus mu s

14:37into n

14:39sin theta

14:43and here is n

14:45cos theta

14:47mu s into n sin theta

14:49transfer it

14:51left side

14:53so this will be n cos theta

14:55minus mu s

14:57into n

14:59sin theta is equal to

15:01mg

15:03here take n common

15:05we will get normal reaction's value

15:07cos theta

15:09minus mu s

15:11sin theta

15:13is equal to

15:15mg

15:17from here normal reaction's value will be

15:23mg divided by

15:25cos theta minus mu s

15:27sin theta

15:29if you have any problem, you can ask

15:31there is no question

15:33till now

15:35say

15:41now see second question

15:43n sin theta

15:45hello

15:53n sin theta

15:55plus fs limiting

15:59cos theta

16:01will be m into ac

16:03see

16:05n sin theta

16:07this component

16:09n sin theta and fs limiting

16:11cos theta

16:13this is centripetal acceleration

16:15m into ac

16:17no problem

16:19put the value

16:21n sin theta

16:23fs limiting's value

16:25mu s into

16:27n

16:29ok

16:31and

16:33this is

16:35cos theta

16:37this will be

16:39mg square upon r

16:41this is v max

16:43here take n common

16:49sin theta plus

16:51mu s

16:53cos theta

16:55this is m v max square

16:57upon r

16:59we have found value of n

17:01put it

17:05write it

17:07first equation and second equation

17:15pi equation first and

17:17second put it

17:19instead of n

17:21mg divided by

17:23cos theta

17:25what happened

17:29very easy

17:31cos theta minus mu s

17:33sin theta

17:35and above

17:37it is written

17:39sin theta plus

17:43mu s

17:45cos theta

17:47this is m v max

17:49square

17:51upon r

17:55cancel m

17:57multiply r

18:01maximum value of v

18:03maximum velocity

18:05body

18:07inclined plane

18:09maximum velocity

18:11no doubt

18:13you

18:15sawrab

18:17how much

18:19v max value

18:23under root

18:25r g

18:27in the bracket

18:29see this

18:31sin theta plus mu s

18:33cos theta

18:35sin theta plus

18:37mu s

18:39cos theta

18:41cos theta minus

18:43mu s sin theta

18:45this is the value

18:47ok

18:49see this is

18:51maximum value of v

18:53from this maximum velocity

18:55any body

18:57circular

18:59banking of road

19:01means curve

19:03from this maximum velocity

19:05any body can move

19:07from this maximum velocity

19:09any body can turn

19:11from this maximum velocity

19:13what will happen

19:15centipetal force

19:17required

19:19car will turn

19:21from this maximum velocity

19:23car will not turn

19:25that is why

19:27in highway

19:29it is written

19:31from this maximum velocity

19:33you should not drive

19:35more speed

19:37more speed

19:39keep driving

19:43ok

19:45take care

19:47ok

19:49ok

19:51ok

19:53ok

19:55ok

20:03ok

20:05write

20:07fast

20:09where are you lost

20:15done

20:17yours

20:19where are you lost

20:23now see

20:25find minimum velocity

20:27what to find

20:29v

20:31minimum value

20:33velocity

20:35circular path

20:37maximum

20:39minimum

20:41friction

20:43limiting

20:45away from the center

20:47down the plane

20:49friction

20:51up the plane

20:55centipetal force

20:57support

20:59for minimum

21:01we will make

21:03FVD

21:05what will be the force

21:07mg

21:09downward

21:11normal reaction

21:13perpendicular

21:15and the friction

21:17in this direction

21:19FS limiting

21:21ok

21:29ok

21:31ok

21:35ok

21:37ok

21:39ok

21:41ok

21:43ok

21:45ok

21:47ok

21:49ok

21:51ok

21:53ok

21:55ok

21:57ok

21:59ok

22:11ok

22:13ok

22:15ok

22:17for fs-limiting

22:21for fs-limiting

22:25for fs-limiting

22:29for fs-limiting

22:33for fs-limiting

22:37for fs-limiting

22:41for fs-limiting

22:45for fs-limiting

22:49for fs-limiting

22:53for fs-limiting

22:57for fs-limiting

23:01for fs-limiting

23:05for fs-limiting

23:09for fs-limiting

23:13for fs-limiting

23:17for fs-limiting

23:21for fs-limiting

23:25for fs-limiting

23:29for fs-limiting

23:33for fs-limiting

23:37for fs-limiting

23:41for fs-limiting

23:45for fs-limiting

23:49for fs-limiting

23:53for fs-limiting

23:57for fs-limiting

24:01for fs-limiting

24:05for fs-limiting

24:09for fs-limiting

24:13for fs-limiting

24:17for fs-limiting

24:21for fs-limiting

24:25for fs-limiting

24:29for fs-limiting

24:33for fs-limiting

24:37common

24:45sine theta

24:49sine theta

24:53sine theta

24:57mu s

25:31cos theta plus mu s sin theta

25:37and this is sin theta minus mu s cos theta

25:48this will be mv minimum square by r

25:52so from here m to am is cancelled

25:56multiply r here

26:00from here v minimum square value will be

26:05rg in the bracket

26:08sin theta minus mu s cos theta

26:14divided by cos theta plus mu s sin theta

26:22we will get v minimum and take its root

26:26shall we play?

26:34tell me what is the value of v minimum

26:37under root

26:40rg in the bracket

26:43sin theta minus mu s cos theta

26:50divided by

26:53cos theta plus mu s sin theta

26:59if you have any doubt, you can ask

27:03you?

27:05not at all?

27:07very good

27:11this is the minimum value of v

27:14on rough inclined plane

27:16and what we have found before is

27:18the maximum value of v

27:23means the overall value of v

27:26minimum and maximum

27:29is a range

27:32we will write it

27:35if you have noted it, then tell me

27:38have you done?

27:41so the value of v

27:53the minimum value of v is

27:56under root

27:59rg in the bracket

28:04sin theta minus mu s cos theta

28:11divided by cos theta

28:15plus mu s sin theta

28:19tell me

28:22what is the maximum value of v?

28:25under root

28:28rg

28:31sin theta plus mu s

28:34cos theta divided by

28:37cos theta minus mu s

28:41sin theta

28:49here

28:52sin theta plus mu s cos theta

28:55divided by cos theta minus mu s sin theta

28:58is v max or v minimum

29:01overall, the minimum value of v will be this

29:04and what will be the maximum value of v?

29:07between this minimum and maximum

29:10you can drive a car at any speed

29:13any vehicle, car, truck

29:16if you are driving on the road

29:19no problem, you will cross safely

29:22how will you cross?

29:25your vehicle will not turn

29:28even if you slow down, it will turn

29:31and

29:34even if you speed up, it will turn

29:37yes, the accident will be big in speeding

29:40but in slowing down

29:43yes

29:46overall, you have to remember

29:49whenever you turn on the road

29:52you have to drive between v minimum

29:55and v max

29:58you don't have to be over smart

30:01it is not a normal road

30:04you can drive at any speed

30:07any doubt?

30:11say that

30:14no?

30:17yes, that's all for today

30:20tomorrow we will start vertical circular motion

30:23we will start

30:26vertical circular motion

30:29we will discuss about it tomorrow

30:32that's all for today

Circular Motion | Circular Motion Class 11 | Banking Of Roads physics Class 11 | Banking Of Roads | Banking Of Roads Physics | Banking Of Roads class 11 JEE | Banking Of Roads class 11 NEET

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